Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and
sum = 22
,
5
/ \
4 8
/ / \
11 13 4
/ \ \
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
/**
* Definition for a binary tree node.
* public class TreeNode {
* public var val: Int
* public var left: TreeNode?
* public var right: TreeNode?
* public init(_ val: Int) {
* self.val = val
* self.left = nil
* self.right = nil
* }
* }
*/
class Solution {
func hasPathSum(_ root: TreeNode?, _ sum: Int) -> Bool {
guard let node = root else { return false }
if let l = node.left, let r = node.right {
return hasPathSum(l, sum - node.val) || hasPathSum(r, sum - node.val)
} else if let r = node.left ?? node.right {
return hasPathSum(r, sum - node.val )
} else {
return sum == node.val
}
}
}