We are given the head node root
of a binary tree, where additionally every node's value is either a 0 or a 1.
Return the same tree where every subtree (of the given tree) not containing a 1 has been removed.
(Recall that the subtree of a node X is X, plus every node that is a descendant of X.)
Example 1: Input: [1,null,0,0,1] Output: [1,null,0,null,1] Explanation: Only the red nodes satisfy the property "every subtree not containing a 1". The diagram on the right represents the answer.![]()
Example 2: Input: [1,0,1,0,0,0,1] Output: [1,null,1,null,1]![]()
Example 3: Input: [1,1,0,1,1,0,1,0] Output: [1,1,0,1,1,null,1]![]()
Note:
- The binary tree will have at most
100 nodes
. - The value of each node will only be
0
or1
.
Companies:
Twitter
Related Topics:
Tree
// OJ: https://leetcode.com/problems/binary-tree-pruning/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(logN)
class Solution {
public:
TreeNode* pruneTree(TreeNode* root) {
if (!root) return NULL;
root->left = pruneTree(root->left);
root->right = pruneTree(root->right);
return !root->left && !root->right && !root->val ? NULL : root;
}
};