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Copy path807.MaxIncreasetoKeepCitySkyline.py
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807.MaxIncreasetoKeepCitySkyline.py
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"""
In a 2 dimensional array grid, each value grid[i][j] represents the height
of a building located there. We are allowed to increase the height of any
number of buildings, by any amount (the amounts can be different for
different buildings). Height 0 is considered to be a building as well.
At the end, the "skyline" when viewed from all four directions of the grid,
i.e. top, bottom, left, and right, must be the same as the skyline of the
original grid. A city's skyline is the outer contour of the rectangles
formed by all the buildings when viewed from a distance. See the following
example.
What is the maximum total sum that the height of the buildings can be
increased?
Example:
Input: grid = [[3,0,8,4],[2,4,5,7],[9,2,6,3],[0,3,1,0]]
Output: 35
Explanation:
The grid is:
[ [3, 0, 8, 4],
[2, 4, 5, 7],
[9, 2, 6, 3],
[0, 3, 1, 0] ]
The skyline viewed from top or bottom is: [9, 4, 8, 7]
The skyline viewed from left or right is: [8, 7, 9, 3]
The grid after increasing the height of buildings without affecting skylines
is:
gridNew = [ [8, 4, 8, 7],
[7, 4, 7, 7],
[9, 4, 8, 7],
[3, 3, 3, 3] ]
Notes:
- 1 < grid.length = grid[0].length <= 50.
- All heights grid[i][j] are in the range [0, 100].
- All buildings in grid[i][j] occupy the entire grid cell: that is,
they are a 1 x 1 x grid[i][j] rectangular prism.
"""
#Difficulty: Medium
#133 / 133 test cases passed.
#Runtime: 64 ms
#Memory Usage: 14.2 MB
#Runtime: 64 ms, faster than 97.89% of Python3 online submissions for Max Increase to Keep City Skyline.
#Memory Usage: 14.2 MB, less than 7.78% of Python3 online submissions for Max Increase to Keep City Skyline.
class Solution:
def maxIncreaseKeepingSkyline(self, grid: List[List[int]]) -> int:
total_increase = 0
horozontal = len(grid)
vertical = len(grid[0])
top_bottom = [float(-inf)] * vertical
left_right = [float(-inf)] * horozontal
for i in range(horozontal):
left_right[i] = max(grid[i])
for j in range(vertical):
top_bottom[j] = max(top_bottom[j], grid[i][j])
for i in range(horozontal):
for j in range(vertical):
total_increase += min(left_right[i], top_bottom[j]) - grid[i][j]
return total_increase