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add leetcode 783
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/**
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* Definition for a binary tree node.
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* function TreeNode(val, left, right) {
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* this.val = (val===undefined ? 0 : val)
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* this.left = (left===undefined ? null : left)
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* this.right = (right===undefined ? null : right)
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* }
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*/
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/**
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* @param {TreeNode} root
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* @return {number}
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* Time O(n) where n is the number of nodes
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* Space O(h) where h is the hight of the tree
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*/
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// We create a class to keep track of the minimum height difference and the previous node
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class TreeNodeInfo {
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constructor(minHeightDiff, prevNode) {
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this.minHeightDiff = minHeightDiff;
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this.prevNode = prevNode;
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}
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}
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// This function returns the minimum height difference of a binary search tree
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function getMinimumHeightDiff(root) {
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const treeNodeInfo = new TreeNodeInfo(Infinity, null); // Initialize minimum height difference to be infinity and previous node to be null
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traverseInOrder(root, treeNodeInfo); // Start traversing the tree in order
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return treeNodeInfo.minHeightDiff; // Return minimum height difference after traversing the tree
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}
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// This function traverses a binary search tree in order and updates the minimum height difference and previous node information
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function traverseInOrder(node, treeNodeInfo) {
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if (node === null) return; // Base case
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traverseInOrder(node.left, treeNodeInfo); // Traverse left subtree
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if (treeNodeInfo.prevNode !== null) {
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// If previous node is not null, update the minimum height difference
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treeNodeInfo.minHeightDiff = Math.min(
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treeNodeInfo.minHeightDiff,
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node.val - treeNodeInfo.prevNode.val
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);
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}
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treeNodeInfo.prevNode = node; // Update previous node to be the current node
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traverseInOrder(node.right, treeNodeInfo); // Traverse right subtree
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}

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