Create Solution.py

Author: chandrikadeb7

Determine if String Halves Are Alike/Solution.py

@@ -0,0 +1,22 @@
+class Solution:
+    def countVowel(self, s):
+        count = 0
+        for ch in s:
+            if ch=='a' or ch == 'A' or ch == 'e' or ch == 'E' or ch == 'i' or ch == 'I' or ch == 'o' or ch == 'O' or ch == 'u' or ch == 'U':
+                count = count + 1
+            else:
+                continue
+        return count    
+    def halvesAreAlike(self, s: str) -> bool:
+        l = len(s)
+        n = l//2
+        s1 = s[:n]
+        s2 = s[n:]
+        
+        m = self.countVowel(s1)
+        n = self.countVowel(s2)
+        
+        if m==n:
+            return True
+        else:
+            return False