add 181-185 sql

Author: Danieldu

SQL/181.employees-earning-more-than-their-managers.sql

@@ -0,0 +1,22 @@
+--
+-- @lc app=leetcode id=181 lang=mysql
+--
+-- [181] Employees Earning More Than Their Managers
+--
+
+-- @lc code=start
+# Write your MySQL query statement below
+
+SELECT 
+  e.name AS Employee
+FROM 
+  Employee e
+WHERE 
+  e.managerId IS NOT NULL
+  AND e.salary > (
+    SELECT m.salary
+    FROM Employee m
+    WHERE m.id = e.managerId
+  );
+-- @lc code=end
+

SQL/182.duplicate-emails.sql

@@ -0,0 +1,18 @@
+--
+-- @lc app=leetcode id=182 lang=mysql
+--
+-- [182] Duplicate Emails
+--
+
+-- @lc code=start
+# Write your MySQL query statement below
+SELECT
+  email AS Email
+FROM
+  Person
+GROUP BY
+  email
+HAVING
+  COUNT(*) > 1;
+-- @lc code=end
+

SQL/183.customers-who-never-order.sql

@@ -6,6 +6,13 @@
 
 -- @lc code=start
 # Write your MySQL query statement below
-select name as Customers from Customers where Customers.id not in (select customerId from Orders)
+SELECT 
+    name AS Customers 
+FROM 
+    Customers 
+WHERE 
+    Customers.id NOT IN (
+        SELECT customerId FROM Orders
+    )
 -- @lc code=end
 

SQL/184.department-highest-salary.sql

@@ -0,0 +1,27 @@
+--
+-- @lc app=leetcode id=184 lang=mysql
+--
+-- [184] Department Highest Salary
+--
+
+-- @lc code=start
+# Write your MySQL query statement below
+SELECT
+  d.name       AS Department,
+  e.name       AS Employee,
+  e.salary     AS Salary
+FROM
+  Employee e
+  JOIN Department d
+    ON e.departmentId = d.id
+WHERE
+  e.salary = (
+    SELECT MAX(salary)
+    FROM Employee
+    WHERE departmentId = e.departmentId
+  )
+ORDER BY
+  d.name,
+  e.name;
+-- @lc code=end
+

SQL/185.department-top-three-salaries.sql

@@ -0,0 +1,29 @@
+--
+-- @lc app=leetcode id=185 lang=mysql
+--
+-- [185] Department Top Three Salaries
+--
+
+-- @lc code=start
+# Write your MySQL query statement below
+SELECT
+  d.name       AS Department,
+  e.name       AS Employee,
+  e.salary     AS Salary
+FROM
+  Employee e
+  JOIN Department d
+    ON e.departmentId = d.id
+WHERE
+  (
+    SELECT COUNT(DISTINCT salary)
+    FROM Employee x
+    WHERE
+      x.departmentId = e.departmentId
+      AND x.salary > e.salary
+  ) < 3
+ORDER BY
+  Department    ASC,
+  Salary        DESC;
+-- @lc code=end
+