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783.minimum-distance-between-bst-nodes.cpp
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/*
* @lc app=leetcode id=783 lang=cpp
*
* [783] Minimum Distance Between BST Nodes
*
* https://leetcode.com/problems/minimum-distance-between-bst-nodes/description/
*
* algorithms
* Easy (50.94%)
* Total Accepted: 39.7K
* Total Submissions: 78K
* Testcase Example: '[4,2,6,1,3,null,null]'
*
* Given a Binary Search Tree (BST) with the root node root, return the minimum
* difference between the values of any two different nodes in the tree.
*
* Example :
*
*
* Input: root = [4,2,6,1,3,null,null]
* Output: 1
* Explanation:
* Note that root is a TreeNode object, not an array.
*
* The given tree [4,2,6,1,3,null,null] is represented by the following
* diagram:
*
* 4
* / \
* 2 6
* / \
* 1 3
*
* while the minimum difference in this tree is 1, it occurs between node 1 and
* node 2, also between node 3 and node 2.
*
*
* Note:
*
*
* The size of the BST will be between 2 and 100.
* The BST is always valid, each node's value is an integer, and each node's
* value is different.
*
*/
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int prev;
int minn;
void callme(TreeNode* root){
if(root == NULL) return;
callme(root->left);
if(prev!=INT_MAX && root->val - prev < minn)
minn = root->val - prev;
prev = root->val;
callme(root->right);
}
int minDiffInBST(TreeNode* root) {
minn = INT_MAX;
prev = INT_MAX;
callme(root);
return minn;
}
};