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Copy path88.merge-sorted-array.cpp
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88.merge-sorted-array.cpp
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/*
* @lc app=leetcode id=88 lang=cpp
*
* [88] Merge Sorted Array
*
* https://leetcode.com/problems/merge-sorted-array/description/
*
* algorithms
* Easy (34.00%)
* Total Accepted: 301.6K
* Total Submissions: 885.8K
* Testcase Example: '[1,2,3,0,0,0]\n3\n[2,5,6]\n3'
*
* Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as
* one sorted array.
*
* Note:
*
*
* The number of elements initialized in nums1 and nums2 are m and n
* respectively.
* You may assume that nums1 has enough space (size that is greater or equal to
* m + n) to hold additional elements from nums2.
*
*
* Example:
*
*
* Input:
* nums1 = [1,2,3,0,0,0], m = 3
* nums2 = [2,5,6], n = 3
*
* Output: [1,2,2,3,5,6]
*
*
*/
class Solution {
public:
void merge(vector<int>& nums1, int m, vector<int>& nums2, int n) {
int i=m-1, j=n-1;
int k = m+n-1;
while(j>=0 && i>=0){
cout<<i<<":"<<j<<":"<<k<<" ";
if(nums2[j] > nums1[i]){
nums1[k] = nums2[j];
j--;k--;
}else{
nums1[k] = nums1[i];
i--;k--;
}
}
if(i==-1){
while(k>=0){
nums1[k] = nums2[j];
j--;k--;
}
}
}
};