-
Notifications
You must be signed in to change notification settings - Fork 0
/
Copy path908.smallest-range-i.cpp
77 lines (75 loc) · 1.22 KB
/
908.smallest-range-i.cpp
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
/*
* @lc app=leetcode id=908 lang=cpp
*
* [908] Smallest Range I
*
* https://leetcode.com/problems/smallest-range-i/description/
*
* algorithms
* Easy (64.88%)
* Total Accepted: 26.9K
* Total Submissions: 41.5K
* Testcase Example: '[1]\n0'
*
* Given an array A of integers, for each integer A[i] we may choose any x with
* -K <= x <= K, and add x to A[i].
*
* After this process, we have some array B.
*
* Return the smallest possible difference between the maximum value of B and
* the minimum value of B.
*
*
*
*
*
*
*
* Example 1:
*
*
* Input: A = [1], K = 0
* Output: 0
* Explanation: B = [1]
*
*
*
* Example 2:
*
*
* Input: A = [0,10], K = 2
* Output: 6
* Explanation: B = [2,8]
*
*
*
* Example 3:
*
*
* Input: A = [1,3,6], K = 3
* Output: 0
* Explanation: B = [3,3,3] or B = [4,4,4]
*
*
*
*
* Note:
*
*
* 1 <= A.length <= 10000
* 0 <= A[i] <= 10000
* 0 <= K <= 10000
*
*
*
*
*/
class Solution {
public:
int smallestRangeI(vector<int>& A, int K) {
int minn = INT_MAX, maxx = INT_MIN;
for(auto e: A)
minn = min(minn, e), maxx = max(maxx, e);
return min(max(maxx-minn-2*K, 0), maxx-minn);
}
};