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30 Days Of Python: Day 16 - Python Data Time

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Author: Fernando Vicentin Pavanello
First Edition: March, 2022

<< Day 15 | Day 17 >>

30 Days of Python

📘 Day 16

Python datetime

Python has got datetime module to handle date and time.

import datetime
print(dir(datetime))
['MAXYEAR', 'MINYEAR', '__builtins__', '__cached__', '__doc__', '__file__', '__loader__', '__name__', '__package__', '__spec__', 'date', 'datetime', 'datetime_CAPI', 'sys', 'time', 'timedelta', 'timezone', 'tzinfo']

With dir or help built-in commands it is possible to know the available functions in a certain module. As you can see, in the datetime module there are many functions, but we will focus on date, datetime, time and timedelta. Let se see them one by one.

Getting datetime Information

from datetime import datetime
now = datetime.now()
print(now)                      # 2022-03-27 10:03:34.094907
day = now.day                   # 27
month = now.month               # 3
year = now.year                 # 2022
hour = now.hour                 # 10
minute = now.minute             # 3
second = now.second
timestamp = now.timestamp()
print(day, month, year, hour, minute)
print('timestamp', timestamp)
print(f'{day}/{month}/{year}, {hour}:{minute}') # 27/3/2022 10:03

Timestamp or Unix timestamp is the number of seconds elapsed from 1st of January 1970 UTC.

Formatting Date Output Using strftime

from datetime import datetime
new_year = datetime(2021, 1, 1)
print(new_year)     # 2021-01-01 00:00:00
day = new_year.day
month = new_year.month
year = new_year.year
hour = new_year.hour
minute = new_year.minute
second = new_year.second
print(day, month, year, hour, minute) # 1 1 2021 0 0
print(f'{day}/{month}/{year}, {hour}:{minute}') # 1/1/2021, 0:0

Formatting date time using strftime method and the documentation can be found here.

from datetime import datetime
# current date and time 
now = datetime.now()
t = now.strftime('%H:%M:%S')
print('time:', t)
time_one = now.strftime('%m/%d/%Y, %H:%M:%S')
# mm/dd/YY H:M:S format
print('time one:', time_one)
time_two = now.strftime('%d/%m/%Y, %H:%M:%S')
# dd/mm/YY H:M:S format
print("time two:", time_two)
time: 10:23:02
time one: 03/27/2022, 10:23:02
time two: 27/03/2022, 10:23:02

String to Time Using strptime

Here is a documentation hat helps to understand the format.

from datetime import datetime
date_string = "23 March, 2022"
print("date_string =", date_string)
date_object = datetime.strptime(date_string, "%d %B, %Y")
print("date_object =", date_object)
date_string = 23 March, 2022
date_object = 2022-03-23 00:00:00

Using date from datetime

from datetime import date
d = date(2022, 1, 1)
print(d)
print('Current date:', d.today())    # 2022-27-03
# date object of today's date
today = date.today()
print("Current year:", today.year)   # 2022
print("Current month:", today.month) # 3
print("Current day:", today.day)     # 27

Time Objects to Represent Time

from datetime import time
# time(hour = 0, minute = 0, second = 0)
a = time()
print("a =", a)
# time(hour, minute and second)
b = time(10, 30, 50)
print("b =", b)
# time(hour, minute and second)
c = time(hour=10, minute=30, second=50)
print("c =", c)
# time(hour, minute, second, microsecond)
d = time(10, 30, 50, 200555)
print("d =", d)

output
a = 00:00:00
b = 10:30:50
c = 10:30:50
d = 10:30:50.200555

Difference Between Two Points in Time Using

today = date(year=2022, month=3, day=27)
new_year = date(year=2023, month=1, day=1)
time_left_for_newyear = new_year - today
# Time left for new year:  27 days, 0:00:00
print('Time left for new year: ', time_left_for_newyear) # Time left for new year:  280 days, 0:00:00

t1 = datetime(year = 2022, month = 3, day = 27, hour = 10, minute = 30, second = 0)
t2 = datetime(year = 2023, month = 1, day = 1, hour = 0, minute = 0, second = 0)
diff = t2 - t1
print('Time left for new year:', diff) # Time left for new year: 279 days, 13:30:00

Difference Between Two Points in Time Using timedelata

from datetime import timedelta
t1 = timedelta(weeks=12, days=10, hours=4, seconds=20)
t2 = timedelta(days=7, hours=5, minutes=3, seconds=30)
t3 = t1 - t2
print("t3 =", t3)
    t3 = 86 days, 22:56:50

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