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binary tree - bfs recu O(n) O(n) + iter O(n) O(n)
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/**
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* Definition for a binary tree node.
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* function TreeNode(val, left, right) {
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* this.val = (val===undefined ? 0 : val)
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* this.left = (left===undefined ? null : left)
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* this.right = (right===undefined ? null : right)
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* }
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*/
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/**
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* @param {TreeNode} root
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* @return {number[][]}
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*/
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// p: root of bi tree;
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// r: array
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// bfs recursive
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var levelOrder = function (root) {
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if (!root) return [];
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const result = [];
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const lo = (root, level, result) => {
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if (!root) return;
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if (!result[level]) result[level] = [];
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result[level].push(root.val);
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lo(root.left, level + 1, result);
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lo(root.right, level + 1, result);
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};
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lo(root, 0, result);
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return result;
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};
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// bfs iterative
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// var levelOrder = function(root) {
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// if (!root) return [];
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// const queue = [[root, 0]];
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// const result = [];
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// while (queue.length > 0) {
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// const [c, level] = queue.shift();
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// if (!result[level]) result[level] = [];
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// result[level].push(c.val);
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// c.left && queue.push([c.left, level + 1]);
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// c.right && queue.push([c.right, level + 1]);
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// }
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// return result;
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// };

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