Find the parity outlier

Author: meloryayala

FindParityOutlier.js

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+
+//You are given an array (which will have a length of at least 3, but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer (N). Write a method that takes the array as an argument and returns this "outlier" (N).
+
+function findOutlier(integers){
+    var amoutEven = 0
+    var amoutOdd = 0
+    if(Math.abs(integers[0] % 2) == 0) {
+        amoutEven++
+    } else {
+        amoutOdd++
+    }
+
+    if(Math.abs(integers[1] % 2) == 0) {
+        amoutEven++
+    } else {
+        amoutOdd++
+    }
+
+    if(Math.abs(integers[2] % 2) == 0) {
+        amoutEven++
+    } else {
+        amoutOdd++
+    }
+
+    var isEvenArray = amoutEven > amoutOdd
+
+
+    for (const integer of integers){
+        const resto =  Math.abs(integer % 2)
+
+        if (isEvenArray && resto == 1){
+            return integer
+        } else if (!isEvenArray && resto == 0){
+            return integer
+        }
+    }
+}