DetermineIfStringHalvesAreAlike1704.kt

package easy

/**
 * You are given a string s of even length. Split this string into two halves of equal lengths, and let a be the first half and b be the second half.

Two strings are alike if they have the same number of vowels ('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U'). Notice that s contains uppercase and lowercase letters.

Return true if a and b are alike. Otherwise, return false.



Example 1:

Input: s = "book"
Output: true
Explanation: a = "bo" and b = "ok". a has 1 vowel and b has 1 vowel. Therefore, they are alike.
Example 2:

Input: s = "textbook"
Output: false
Explanation: a = "text" and b = "book". a has 1 vowel whereas b has 2. Therefore, they are not alike.
Notice that the vowel o is counted twice.


Constraints:

2 <= s.length <= 1000
s.length is even.
s consists of uppercase and lowercase letters.
 */
fun halvesAreAlike(s: String): Boolean {
    var countA = 0
    var countB=0

    for(i in 0 until s.length/2)
        if(s[i].isVowelUpperLowerCase())
            countA++

    for(i in  s.length/2 until s.length)
        if(s[i].isVowelUpperLowerCase())
            countB++

    return countA == countB
}
fun Char.isVowelUpperLowerCase() = charArrayOf('a', 'e', 'i', 'o', 'u', 'A', 'E', 'I', 'O', 'U').any{ it==this }