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Author: mnabeel11

Moaz_Nabeel_sql_project.sql

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+/* Welcome to the SQL mini project. For this project, you will use
+Springboard' online SQL platform, which you can log into through the
+following link:
+
+https://sql.springboard.com/
+Username: student
+Password: learn_sql@springboard
+
+The data you need is in the "country_club" database. This database
+contains 3 tables:
+    i) the "Bookings" table,
+    ii) the "Facilities" table, and
+    iii) the "Members" table.
+
+Note that, if you need to, you can also download these tables locally.
+
+In the mini project, you'll be asked a series of questions. You can
+solve them using the platform, but for the final deliverable,
+paste the code for each solution into this script, and upload it
+to your GitHub.
+
+Before starting with the questions, feel free to take your time,
+exploring the data, and getting acquainted with the 3 tables. */
+
+
+
+/* Q1: Some of the facilities charge a fee to members, but some do not.
+Please list the names of the facilities that do. */
+
+SELECT name
+FROM Facilities
+WHERE membercost !=0
+
+
+/* Q2: How many facilities do not charge a fee to members? */
+
+SELECT COUNT(*) FROM Facilities
+WHERE membercost != 0
+
+
+/* Q3: How can you produce a list of facilities that charge a fee to members,
+where the fee is less than 20% of the facility's monthly maintenance cost?
+Return the facid, facility name, member cost, and monthly maintenance of the
+facilities in question. */
+
+SELECT facid, name, membercost, monthlymaintenance FROM Facilities
+WHERE membercost <  monthlymaintenance * 0.2 and membercost != 0
+
+/* Q4: How can you retrieve the details of facilities with ID 1 and 5?
+Write the query without using the OR operator. */
+
+SELECT * FROM Facilities 
+WHERE facid IN (1,5)
+
+/* Q5: How can you produce a list of facilities, with each labelled as
+'cheap' or 'expensive', depending on if their monthly maintenance cost is
+more than $100? Return the name and monthly maintenance of the facilities
+in question. */
+
+SELECT name, monthlymaintenance
+	CASE WHEN monthlymaintenance > 100 THEN 'expensive'
+		ELSE 'cheap' END AS price
+	FROM Facilities 
+
+
+/* Q6: You'd like to get the first and last name of the last member(s)
+who signed up. Do not use the LIMIT clause for your solution. */
+
+SELECT  firstname, surname, joindate FROM Members
+ ORDER BY joindate DESC
+
+
+/* Q7: How can you produce a list of all members who have used a tennis court?
+Include in your output the name of the court, and the name of the member
+formatted as a single column. Ensure no duplicate data, and order by
+the member name. */
+
+SELECT DISTINCT concat(firstname, ' ', surname) AS member_name, name FROM Bookings
+JOIN Members
+ON Bookings.memid = Members.memid
+JOIN Facilities
+ON Bookings.facid = Facilities.facid
+WHERE name LIKE "Tennis Court%"
+ORDER BY firstname 
+
+/* Q8: How can you produce a list of bookings on the day of 2012-09-14 which
+will cost the member (or guest) more than $30? Remember that guests have
+different costs to members (the listed costs are per half-hour 'slot'), and
+the guest user's ID is always 0. Include in your output the name of the
+facility, the name of the member formatted as a single column, and the cost.
+Order by descending cost, and do not use any subqueries. */
+
+SELECT DISTINCT firstname, CASE WHEN firstname = 'GUEST' THEN guestcost ELSE membercost END AS cost,
+name, concat(firstname, ' ', surname) AS member_name FROM Bookings
+JOIN Members
+ON Bookings.memid = Members.memid
+JOIN Facilities
+ON Bookings.facid = Facilities.facid
+WHERE starttime LIKE "2012-09-14%"
+ORDER BY cost DESC 
+
+/* Q9: This time, produce the same result as in Q8, but using a subquery. */
+
+SELECT firstname, CASE WHEN firstname = 'GUEST' THEN guestcost ELSE membercost END AS cost,
+name, concat(firstname, ' ', surname) AS member_name FROM (
+SELECT *
+FROM Bookings
+WHERE starttime LIKE "2012-09-14%"
+) AS test
+JOIN Members
+ON test.memid = Members.memid
+JOIN Facilities
+ON test.facid = Facilities.facid
+ORDER BY cost DESC
+
+
+/* Q10: Produce a list of facilities with a total revenue less than 1000.
+The output of facility name and total revenue, sorted by revenue. Remember
+that there's a different cost for guests and members! */
+
+SELECT *
+FROM (
+SELECT name, SUM(CASE WHEN firstname = 'GUEST' THEN guestcost ELSE membercost END) AS cost
+FROM Bookings     
+JOIN Members
+ON Bookings.memid = Members.memid
+JOIN Facilities
+ON Bookings.facid = Facilities.facid
+Group By name
+ORDER BY cost DESC
+) AS test
+Where cost < 1000