Create 37.2 gmail validator.java

Author: prokrishpatel

37.2 gmail validator.java

@@ -0,0 +1,74 @@
+/*
+Ask the user to give his/her the Gmail id , check Gmail id is in proper format or not ? and count the number of charecters excluding @gmail.com
+let rules for valid mail id are
+1. only special symbol allowed is (.) and that must not be in staring or ending.
+2. @gmail.com must be prsent at last.
+
+Input Format
+
+First line must be a mail id
+
+for Example
+
+Input Format
+bhimasen.moharana@gmail.com
+
+Output Format
+valid 17
+
+Constraints
+
+input must be a Gmail id
+
+Output Format
+
+First line prints "valid" or "invalid"
+Secondline prints Number of chars presenst inthe mail id excluding @gmail.com
+
+Sample Input 0
+
+bhimasen.moharana@lpu.co.in
+Sample Output 0
+
+invalid
+17
+Explanation 0
+
+invalid because it is not a Gmail id.
+and number of charecter =17
+*/
+
+import java.io.*;
+import java.util.*;
+
+public class Solution {
+
+    public static void main(String[] args) {
+        /* Enter your code here. Read input from STDIN. Print output to STDOUT. Your class should be named Solution. */
+        Scanner sc = new Scanner(System.in);
+        String gmail = sc.next();
+        char []check = gmail.toCharArray(); 
+        boolean ans = true;
+        int count =0;
+        if(gmail.endsWith("@gmail.com"))
+        {
+            int n = gmail.indexOf("@gmail.com");
+            for(int i=0;i<n;i++)
+            {
+                if(!((check[i] >= 'A' && check[i] <= 'Z') || (check[i] >='a') && (check[i] <= 'j')))
+                {
+                    System.out.println("invalid");
+                    ans = false;
+                }    
+            }
+            if(ans)
+                System.out.println("valid");
+        }
+        else
+        {
+            System.out.println("invalid");
+        }
+        int ct = gmail.indexOf("@");
+        System.out.print(ct);
+    }
+}