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1266-minimum-time-visiting-all-points/README.md

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+<h2><a href="https://leetcode.com/problems/minimum-time-visiting-all-points/">1266. Minimum Time Visiting All Points</a></h2><h3>Easy</h3><hr><div><p>On a 2D plane, there are <code>n</code> points with integer coordinates <code>points[i] = [x<sub>i</sub>, y<sub>i</sub>]</code>. Return <em>the <strong>minimum time</strong> in seconds to visit all the points in the order given by </em><code>points</code>.</p>
+
+<p>You can move according to these rules:</p>
+
+<ul>
+	<li>In <code>1</code> second, you can either:
+
+	<ul>
+		<li>move vertically by one&nbsp;unit,</li>
+		<li>move horizontally by one unit, or</li>
+		<li>move diagonally <code>sqrt(2)</code> units (in other words, move one unit vertically then one unit horizontally in <code>1</code> second).</li>
+	</ul>
+	</li>
+	<li>You have to visit the points in the same order as they appear in the array.</li>
+	<li>You are allowed to pass through points that appear later in the order, but these do not count as visits.</li>
+</ul>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2019/11/14/1626_example_1.PNG" style="width: 500px; height: 428px;">
+<pre><strong>Input:</strong> points = [[1,1],[3,4],[-1,0]]
+<strong>Output:</strong> 7
+<strong>Explanation: </strong>One optimal path is <strong>[1,1]</strong> -&gt; [2,2] -&gt; [3,3] -&gt; <strong>[3,4] </strong>-&gt; [2,3] -&gt; [1,2] -&gt; [0,1] -&gt; <strong>[-1,0]</strong>   
+Time from [1,1] to [3,4] = 3 seconds 
+Time from [3,4] to [-1,0] = 4 seconds
+Total time = 7 seconds</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre><strong>Input:</strong> points = [[3,2],[-2,2]]
+<strong>Output:</strong> 5
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>points.length == n</code></li>
+	<li><code>1 &lt;= n&nbsp;&lt;= 100</code></li>
+	<li><code>points[i].length == 2</code></li>
+	<li><code>-1000&nbsp;&lt;= points[i][0], points[i][1]&nbsp;&lt;= 1000</code></li>
+</ul>
+</div>