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Time: 120 ms (73.80%), Space: 27.9 MB (85.25%) - LeetHub
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/**
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* Definition for a binary tree node.
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* struct TreeNode {
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* int val;
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* TreeNode *left;
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* TreeNode *right;
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* TreeNode() : val(0), left(nullptr), right(nullptr) {}
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* TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
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* TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
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* };
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*/
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class Solution {
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public:
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array<vector<TreeNode*>, 22> memo;
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vector<TreeNode*> allPossibleFBT(int n) {
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if(n == 1){
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TreeNode* root = new TreeNode(0);
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return {root};
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}
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vector<TreeNode*> ans;
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if(n%2){
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for(int i=1; i<n; i+=2){
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vector<TreeNode*> ltree;
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vector<TreeNode*> rtree;
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if(memo[i].size())
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ltree = memo[i];
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else
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ltree = allPossibleFBT(i);
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if(memo[n-i-1].size())
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rtree = memo[n-i-1];
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else
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rtree = allPossibleFBT(n-i-1);
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for(auto lt:ltree){
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for(auto rt:rtree){
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TreeNode* root = new TreeNode(0);
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root->left = lt;
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root->right = rt;
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ans.push_back(root);
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}
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}
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}
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memo[n] = ans;
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return ans;
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}
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return {};
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}
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};

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